2x^2+56x-384=0

Solution for 2x^2+56x-384=0 equation:

2x^2+56x-384=0

a = 2; b = 56; c = -384;
Δ = b2-4ac
Δ = 562-4·2·(-384)
Δ = 6208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6208}=\sqrt{64*97}=\sqrt{64}*\sqrt{97}=8\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-8\sqrt{97}}{2*2}=\frac{-56-8\sqrt{97}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+8\sqrt{97}}{2*2}=\frac{-56+8\sqrt{97}}{4}
$